**Online Discussions:**

Associated with each quiz will be a quiz discussion. After you make your first attempt at

a quiz, then the discussion for that quiz will open to you. The online discussionswill be

held in the D2L course site. For each quiz, you are to post at least one question from the

quiz that you do not understand, got incorrect, or had difficulty answering. This will be your original

post. This question must be one that someone else has not already posted. In addition, you

are to reply to the original question posted by at least one other student and explain the answer

to his or her question. Your original question is worth 8 points and your reply to another student is

worth 8 points. Note, if you post the same question, then you will get no credit for your posting!

Use complete sentences and good grammar (4 points)-- no slang or abbreviations! You are

expected to use the equation editor in D2L. Attachments in the discussion area are not acceptable

-- do not use them.

If you get all questions correct on your first attempt, then your original post is to be a word/application

problem that you construct. However, only those who get ALL questions correct on their first attempt

can post a self-made word/application problem.

Examples of Quiz Discussion Posts and Reply:

Good Original Post

Question 5 on my on quiz asked me to find the roots of the equation

x^{2}- 6x - 16 = 0. I factored to get x(x - 6) = 16 and got x = 16 and

x = 22. What am I doing wrong?

**Bad Original Post **

Question 5 what's up w/ this?

Good Reply I

I used my TI-83 calculator. Place the equation y = x^{2} - 6x - 16 in you calculator.

Graph the equation and then use the feature to find the zeros, which are the

roots, You get x = 8 or x = -2

Good Reply II

I agree with Good Reply I, but remember that x is a root which is an x-intercept.

Therefore I solved by factoring

x^{2} - 6x - 16 = 0

(x -8)(x +2) = 0

so x = 8 or x =-2.

**Bad Reply I**

I agree with what everyone has said.

**Bad Reply II**

I got just like you x = 8 or x = -2.

*Page last updated: October 15, 2012*